Inequality Calculator
Solve ax + b ⧋ c for x.
Inequalities feel like equations until you divide by a negative and have to flip the symbol. This calculator solves linear (ax + b < c), quadratic (ax² + bx + c ≤ 0) and absolute value |ax + b| > c inequalities step by step, returns the solution in interval notation, set notation and plotted form, and reminds you of every sign-flip along the way.
How to solve an inequality
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1
Enter the inequality
Type as you would write it: `2x + 3 > 7`, `x^2 - 4 <= 0`, `|3x + 1| < 5`.
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2
The tool classifies the form
Linear, quadratic or absolute-value: different strategies apply.
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3
Step-by-step solution
Every algebraic step is shown, with sign-flips highlighted.
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4
Read the result
Interval notation, set-builder notation, and a number-line plot.
Solving each inequality type
Linear inequalities
ax + b < c (or ≤, >, ≥)
- Subtract b from both sides.
- Divide by a.
- If a is negative, flip the inequality.
Example: -2x + 5 > 9 → -2x > 4 → x < -2 (division by -2 flips > to <).
Quadratic inequalities
ax² + bx + c ≤ 0
- Find the roots with the quadratic formula.
- Classify by a’s sign and inequality direction:
| Case | ≤ 0 solution |
≥ 0 solution |
|---|---|---|
| a > 0 | between roots | outside roots |
| a < 0 | outside roots | between roots |
- Strict (
<,>) excludes roots; non-strict (≤,≥) includes them.
Absolute value inequalities
|ax + b| < c(with c > 0) →-c < ax + b < c. Solve as a double inequality.|ax + b| > c→ax + b > cORax + b < -c. Solve each branch separately and union the results.- If c is negative, the “< c” form has no solution and the “> c” form is all real numbers.
Interval notation conventions
(a, b), open interval, endpoints excluded.[a, b], closed interval, endpoints included.(a, b], half-open.(-∞, 3), unbounded on the left.(-∞, 3) ∪ (5, ∞), union of two disjoint intervals.
Common traps
- Forgetting to flip when multiplying or dividing by a negative.
- Using a strict symbol (
<) but including the endpoint in the answer. - Solving
|x - 3| > 5and combining the two cases with AND instead of OR.
Frequently Asked Questions
Whenever you multiply or divide both sides by a negative number. Also when you take reciprocals of both sides (if both sides have the same sign). Never when adding or subtracting.
A quadratic with a > 0 (parabola opening up) is negative only between its roots, so ax² + bx + c < 0 gives one interval. But > 0 gives the two outer intervals, written as a union.
Yes, enter them separated by commas. The tool intersects (AND) the solution sets by default; use the “union” toggle if you want OR semantics.
Yes. The step-by-step view explains every algebraic operation and justifies each sign-flip, in a form suitable for homework submission or exam practice.
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