Arithmetic Sequence Calculator

Nth term

Enter the first term, the common difference and how many terms you want, and this arithmetic sequence calculator returns the nth term, the sum of the first n terms, and a preview of the sequence itself. An arithmetic sequence is one where you add the same fixed amount to get from each term to the next, so it grows (or shrinks) in a perfectly straight line. The results update as you type, with no rounding shortcuts and nothing to install.

How the calculator works

  1. 1

    Enter the first term and difference

    Type the starting value a₁ and the common difference d added between each term.

  2. 2

    Choose how many terms

    Set n, the position of the term you want and the count to sum over.

  3. 3

    Read the results

    See the nth term, the sum of the first n terms and a preview of the sequence.

The arithmetic sequence formulas

An arithmetic sequence has a constant gap, the common difference d, between consecutive terms. Two formulas do all the work:

nth term:  a_n = a₁ + (n − 1) · d
sum:       S_n = n/2 · (2·a₁ + (n − 1) · d)

Here a₁ is the first term, d is the amount added each step (it can be negative for a decreasing sequence), and n is how many terms you are counting. The sum formula is just the average of the first and last term, multiplied by how many terms there are.

A worked example

Take a₁ = 2 and d = 3. The sequence is 2, 5, 8, 11, 14, 17, 20, 23, 26, 29 …

To find the 10th term:

a₁₀ = 2 + (10 − 1) · 3 = 2 + 27 = 29

To add the first 10 terms:

S₁₀ = 10/2 · (2·2 + 9·3) = 5 · (4 + 27) = 5 · 31 = 155

So the 10th term is 29 and the running total is 155.

Terms, differences and partial sums

n aₙ = 2 + (n−1)·3 Sₙ (sum of first n)
1 2 2
2 5 7
5 14 40
10 29 155

Notice each term rises by exactly d = 3, the signature of an arithmetic (not geometric) progression. The partial sum Sₙ grows faster than the terms themselves because every step adds the whole running line, not just the latest value.

A quick sanity check: the sum equals the number of terms times the average of the first and last term. For n = 10 that is 10 · (2 + 29) ÷ 2 = 10 · 15.5 = 155, which matches the table exactly.

Common pitfalls

  • Off-by-one on n. The formula uses (n − 1)·d, not n·d. The first term has zero differences added, so a₁ = 2, not 5.
  • Confusing arithmetic with geometric. Arithmetic sequences add a fixed d; geometric sequences multiply by a fixed ratio. If your gaps keep doubling, you need a geometric tool instead.
  • Negative differences are fine. A common difference of d = −4 gives a falling sequence; the same formulas still apply.

Frequently Asked Questions

A list of numbers where each term differs from the one before it by the same fixed amount, called the common difference. For example 3, 7, 11, 15 has a common difference of 4.

Use a_n = a₁ + (n − 1)·d, where a₁ is the first term, d is the common difference and n is the position you want. This calculator applies it for you instantly.

With S_n = n/2 · (2·a₁ + (n − 1)·d), which equals the number of terms times the average of the first and last term. It works for positive, negative or zero differences.

No. Every calculation runs in your browser session and nothing you type is uploaded, saved or shared. The numbers you enter never leave your session.

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